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Solutions: Class 9 Chemistry

Written by Dr. Ayesha Nadeem (Chemistry)

Solute, solvent and types of solutions, aqueous solutions, saturated and unsaturated solutions, solubility and its change with temperature, concentration units including molarity, and suspensions and colloids compared with true solutions.

Key points

A solution is a homogeneous mixture of two or more substances. The component present in the larger amount is the solvent, and the one dissolved in it is the solute. In sugar solution, sugar is the solute and water is the solvent. A solution has the same composition and properties throughout, and its particles cannot be seen or filtered out.

Solutions can be formed in all three states. Examples:

  • Gas in gas: air (oxygen and other gases in nitrogen).
  • Gas in liquid: carbonated water (carbon dioxide in water).
  • Liquid in liquid: vinegar (ethanoic acid in water).
  • Solid in liquid: salt in water.
  • Solid in solid: brass (zinc in copper), an alloy.
  • Gas in solid: hydrogen in palladium.

Water is called the universal solvent because it dissolves more substances than any other common liquid. Its molecule is polar, and water molecules surround and separate ions and polar molecules. The rule is that like dissolves like. Polar and ionic substances dissolve in polar solvents such as water. Non-polar substances, such as oil, wax and grease, dissolve in non-polar solvents such as petrol, benzene and carbon tetrachloride.

Types of solutions by amount of solute:

  • Unsaturated: contains less solute than the maximum it can dissolve at that temperature. More can still dissolve.
  • Saturated: contains the maximum solute at that temperature. Extra solute stays undissolved and is in dynamic equilibrium with the dissolved solute.
  • Supersaturated: contains more solute than a saturated solution at that temperature. It is unstable, and a small crystal or a shake makes the extra solute crystallise.

Solubility is the maximum mass of solute in grams that dissolves in 100 g of solvent at a given temperature to give a saturated solution. For most solids, solubility increases with temperature, for example potassium nitrate. For a few, such as sodium chloride, it changes very little. For gases, solubility decreases when temperature rises and increases when pressure rises. This is why a soft drink fizzes when the bottle is opened and pressure falls.

Dilute and concentrated are descriptive words. A dilute solution has a small amount of solute relative to solvent and a concentrated solution has a large amount. They do not give numerical values, so chemists use concentration units.

Common concentration units:

  • Percentage by mass (w/w) = mass of solute / mass of solution × 100.
  • Percentage mass by volume (w/v) = mass of solute in g / volume of solution in cm³ × 100.
  • Percentage by volume (v/v) = volume of solute / volume of solution × 100.
  • Parts per million (ppm) = mass of solute / mass of solution × 10⁶.
  • Molarity (M) = moles of solute / volume of solution in dm³. Unit: mol dm⁻³.

A 1 molar (1 M) solution contains one mole of solute in 1 dm³ of solution. The number of moles is mass divided by molar mass. For preparing a standard solution, the measured mass of solute is dissolved in a little water in a volumetric flask, and water is then added up to the mark.

Dilution means adding solvent to reduce concentration. The amount of solute does not change, so M₁V₁ = M₂V₂. To dilute a stock solution, measure V₁ with a pipette, put it in a flask and add water until the volume is V₂.

A suspension has large particles (bigger than about 1000 nm) which are visible. It is cloudy, the particles settle on standing and can be filtered. Muddy water and chalk in water are suspensions. A colloid has medium-size particles (about 1 to 1000 nm). It does not settle and cannot be filtered with ordinary paper. Milk, fog, smoke and ink are colloids.

The Tyndall effect is the scattering of light by colloidal particles, which makes a light beam visible through the colloid. True solutions do not show it. Brownian motion is the continuous zig-zag motion of colloidal particles caused by random collisions with the molecules of the medium. Colloids and suspensions are heterogeneous or look so under a microscope, while a true solution is homogeneous.

Study tip: Write the formula, the unit conversions and the molar mass calculation as separate lines in every numerical. For the colloid, suspension and true solution comparison, use a table with particle size, appearance, settling, filtration and the Tyndall effect, and give one example of each.

Definitions and flashcards

Say the meaning first, then open the card to check.

Solute

The substance that dissolves in a solvent.

Solvent

The substance in which a solute dissolves, usually the larger part.

Saturated solution

A solution holding the maximum solute possible at a given temperature.

Solubility

Grams of solute that dissolve in 100 g of solvent to make a saturated solution.

Molarity

Moles of solute in one dm³ of solution.

Colloid

A mixture with particles of 1 to 1000 nm that do not settle.

Tyndall effect

Scattering of a light beam by colloidal particles.

Suspension

A heterogeneous mixture whose large particles settle on standing.

Formula sheet

NameFormulaWhat it means
MolarityM = n / Vn in moles, V in dm³
Molesn = mass / molar massMass in g, molar mass in g/mol
DilutionM₁V₁ = M₂V₂Moles of solute stay constant
Percentage w/w(mass of solute / mass of solution) × 100Mass of solution = solute + solvent

Short questions with model answers

These are the kind of questions asked for 2, 3 and 5 marks. Try each one before opening the answer.

Why is water called the universal solvent? (2 marks)

Water dissolves a larger number of substances than any other common solvent. Its polar molecules attract and surround ions and polar molecules and separate them.

Differentiate between saturated and supersaturated solutions. (2 marks)

A saturated solution holds the maximum amount of solute at a given temperature and is stable. A supersaturated solution holds more solute than that maximum and is unstable, so the excess crystallises if a seed crystal is added.

How does temperature affect the solubility of solids and gases? (3 marks)

The solubility of most solids increases with temperature because heat helps break the solid's structure. The solubility of gases decreases with temperature because gas molecules gain energy and escape from the liquid. Gas solubility increases with pressure.

Compare true solutions, colloids and suspensions. (5 marks)

A true solution has particles smaller than 1 nm, is clear, does not scatter light, does not settle and passes through filter paper (example: salt in water). A colloid has particles of 1 to 1000 nm, looks cloudy or translucent, shows the Tyndall effect, does not settle and passes through filter paper (example: milk). A suspension has particles larger than 1000 nm, is opaque, settles on standing and is retained by filter paper (example: chalk in water).

What is the Tyndall effect and why do true solutions not show it? (3 marks)

It is the scattering of light by particles in the path of a beam, making the path visible. Colloidal particles are large enough to scatter light. Particles in a true solution are too small to scatter visible light.

State the rule 'like dissolves like' with examples. (2 marks)

Polar and ionic solutes dissolve in polar solvents, so salt dissolves in water. Non-polar solutes dissolve in non-polar solvents, so grease dissolves in petrol.

Numericals with worked steps

4 g of NaOH (Na = 23, O = 16, H = 1) is dissolved in water to make 500 cm³ of solution. Find the molarity.
  1. Molar mass of NaOH = 23 + 16 + 1 = 40 g/mol
  2. Moles = 4 / 40 = 0.1 mol
  3. Volume = 500 cm³ = 0.5 dm³
  4. M = 0.1 / 0.5 = 0.2

Answer: 0.2 mol dm⁻³

10 g of salt is dissolved in 90 g of water. Find the percentage by mass of the solution.
  1. Mass of solution = 10 + 90 = 100 g
  2. Percentage = 10 / 100 × 100 = 10

Answer: 10% w/w

What mass of NaCl (molar mass 58.5 g/mol) is needed to make 250 cm³ of 0.1 M solution?
  1. Volume = 0.25 dm³
  2. Moles = 0.1 × 0.25 = 0.025 mol
  3. Mass = 0.025 × 58.5 = 1.4625

Answer: 1.46 g (to 3 significant figures)

50 cm³ of 2 M solution is diluted to 200 cm³. Find the new molarity.
  1. M₁V₁ = M₂V₂
  2. 2 × 50 = M₂ × 200
  3. M₂ = 100 / 200 = 0.5

Answer: 0.5 mol dm⁻³

Common mistakes

  • Using the volume of the solvent instead of the volume of the whole solution for molarity.
  • Forgetting to convert cm³ to dm³ by dividing by 1000.
  • Using the mass of solvent alone in the denominator of percentage by mass.
  • Saying that a dilute solution is the same as an unsaturated one. They are different ideas.
  • Stating that gas solubility rises with temperature.

Practise this chapter

Practice questions and timed test Printable worksheet

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