MDCAT · Physics · 5 questions
Name: ____________________ Date: ____________
An object moves at 10 m/s in a circle of radius 5 m. What is its centripetal acceleration?
The escape velocity from a planet depends on:
According to Kepler's third law, the square of the orbital period of a planet is proportional to:
The orbital period of a geostationary satellite is:
If the distance between two masses is doubled, the gravitational force between them becomes:
1. A, 2. C, 3. A, 4. D, 5. D
a = v² / r = 100 / 5 = 20 m/s², directed toward the centre.
Escape velocity = sqrt(2GM / R). It depends on the planet's mass and radius, not on the object that escapes.
T² is proportional to r³ for planets orbiting the same star.
It orbits once in 24 hours in the same direction as Earth's spin, so it appears fixed over one point.
Gravitational force follows an inverse square law, so doubling the distance divides the force by 4.