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Oxidation numbers and redox reactions, balancing equations, electrolytic and galvanic cells, electrode potentials, the electrochemical series, Faraday's laws, batteries, fuel cells and corrosion.
Electrochemistry studies the relation between chemical change and electrical energy. Many of its reactions are oxidation reduction (redox) reactions. Oxidation is the loss of electrons, or an increase in oxidation number. Reduction is the gain of electrons, or a decrease in oxidation number. The two always happen together.
The oxidation number is the charge an atom would have if all bonds were ionic. The main rules are:
An oxidising agent gains electrons and is reduced, and a reducing agent loses electrons and is oxidised. In Zn + Cu²⁺ → Zn²⁺ + Cu, zinc is oxidised and is the reducing agent. Cu²⁺ is reduced and is the oxidising agent. Examples of oxidising agents are KMnO₄, K₂Cr₂O₇ and halogens. Common reducing agents are metals, H₂ and Fe²⁺.
Redox equations are balanced by the oxidation number method or the ion electron (half reaction) method. In the half reaction method, split the equation into oxidation and reduction half reactions, balance atoms other than H and O, then balance O with H₂O and H with H⁺ in acid solution, balance the charge with electrons, equalise the electrons and add the halves. For example, in acid: MnO₄⁻ + 8H⁺ + 5e⁻ → Mn²⁺ + 4H₂O.
An electrolytic conductor allows current by movement of ions. Electrolysis is the chemical decomposition of an electrolyte by passing an electric current. The positive electrode is the anode, where oxidation occurs, and the negative electrode is the cathode, where reduction occurs in electrolysis. Cations move to the cathode and anions to the anode. In electrolysis, electrical energy produces a chemical change.
Examples of electrolysis: molten NaCl gives sodium at the cathode and chlorine at the anode (Down's cell). Concentrated brine gives hydrogen at the cathode, chlorine at the anode and NaOH in solution. Water with a little acid gives hydrogen and oxygen in a 2:1 volume ratio. Electroplating coats an object with a metal by making it the cathode in a solution of the metal ions.
Faraday's first law: the mass of a substance deposited or liberated at an electrode is proportional to the quantity of electricity passed, m = ZIt. Faraday's second law: for the same charge, masses of different substances are proportional to their chemical equivalents. One faraday (F) is the charge of one mole of electrons, about 96500 C mol⁻¹. The charge is Q = It, with I in amperes and t in seconds.
A galvanic (voltaic) cell converts chemical energy into electrical energy using a spontaneous redox reaction. In the Daniell cell, a zinc rod dips in ZnSO₄ solution and a copper rod in CuSO₄ solution. Zinc is the anode (oxidation, Zn → Zn²⁺ + 2e⁻). Copper is the cathode (reduction, Cu²⁺ + 2e⁻ → Cu). Electrons flow through the wire from zinc to copper. A salt bridge (KCl or KNO₃) completes the circuit and keeps both solutions neutral. In a galvanic cell the anode is negative and the cathode is positive.
Cell notation puts the anode on the left: Zn(s) | Zn²⁺(aq) || Cu²⁺(aq) | Cu(s). A single vertical line shows a phase boundary and a double line shows the salt bridge. The cell emf is E°cell = E°cathode − E°anode, measured with a voltmeter when no current flows. The Daniell cell emf is about 1.10 V.
The standard electrode potential E° is the potential of a half cell with 1 M ions at 25 °C, measured against the standard hydrogen electrode (SHE), which is given 0.00 V. The SHE is a platinum electrode with H₂ gas at 1 atm bubbling into 1 M H⁺. Values are written as reduction potentials: Li⁺/Li −3.05 V, Na⁺/Na −2.71 V, Mg²⁺/Mg −2.37 V, Zn²⁺/Zn −0.76 V, Fe²⁺/Fe −0.44 V, H⁺/H₂ 0.00 V, Cu²⁺/Cu +0.34 V, Ag⁺/Ag +0.80 V and F₂/F⁻ +2.87 V.
The electrochemical series lists elements in order of electrode potential. A metal higher in the series (more negative E°) is a stronger reducing agent and displaces metals below it from their salt solutions. Metals above hydrogen displace H₂ from dilute acids. If E°cell is positive the reaction is spontaneous. The Nernst equation gives potential at other concentrations: E = E° − (0.0592/n) log Q at 25 °C.
Commercial cells: the dry (Leclanché) cell has a zinc case, a carbon rod and MnO₂ with NH₄Cl paste, giving 1.5 V. The lead acid battery uses Pb as anode and PbO₂ as cathode in H₂SO₄ and gives about 2 V per cell, so six cells give 12 V. It is rechargeable. A fuel cell, such as the hydrogen oxygen cell, makes electricity continuously as fuel is supplied and produces only water. Corrosion is the slow oxidation of metals by the environment. Rusting of iron needs oxygen and water, and is an electrochemical process. It is prevented by painting, galvanising with zinc, and sacrificial anodes of magnesium.
Study tip: Use the memory line 'An Ox, Red Cat': anode is oxidation, reduction is at the cathode. Draw the Daniell cell with all labels, including electron flow, ion flow in the salt bridge and the charge on each electrode. In Faraday questions go step by step: charge, moles of electrons, moles of substance, mass.
Say the meaning first, then open the card to check.
Loss of electrons or increase in oxidation number
Gain of electrons or decrease in oxidation number
Chemical decomposition of an electrolyte by an electric current
The electrode where oxidation takes place
The electrode where reduction takes place
A tube of electrolyte that completes the circuit between half cells
The reference electrode with potential 0.00 V
The tendency of a half cell to gain or lose electrons
The charge of one mole of electrons, about 96500 C
Slow oxidation of a metal by oxygen and moisture in the environment
| Name | Formula | What it means |
|---|---|---|
| Charge | Q = I × t | I in amperes, t in seconds, Q in coulombs |
| Faraday's first law | m = (Q / F) × (M / z) | Mass deposited; z electrons per ion, F = 96500 C mol⁻¹ |
| Cell emf | E°cell = E°cathode − E°anode | Positive value means a spontaneous reaction |
| Nernst equation | E = E° − (0.0592/n) log Q | At 25 °C |
These are the kind of questions asked for 2, 3 and 5 marks. Try each one before opening the answer.
Oxidation is the loss of electrons by an atom or ion. Reduction is the gain of electrons. They always occur together in a redox reaction.
It completes the electrical circuit by allowing ions to move between the half cells. It keeps each solution electrically neutral by supplying ions as charge builds up, and it prevents the solutions from mixing.
The cell has a zinc rod in ZnSO₄ solution and a copper rod in CuSO₄ solution joined by a salt bridge. At the zinc anode: Zn → Zn²⁺ + 2e⁻. At the copper cathode: Cu²⁺ + 2e⁻ → Cu. Electrons flow from zinc to copper through the external wire. The notation is Zn | Zn²⁺ || Cu²⁺ | Cu. The emf is E°cell = 0.34 − (−0.76) = 1.10 V.
A galvanic cell converts chemical energy into electrical energy through a spontaneous reaction, and the anode is negative. An electrolytic cell uses electrical energy to cause a non-spontaneous reaction, and the anode is positive.
The mass of a substance deposited or liberated at an electrode is directly proportional to the quantity of electricity (charge) passed through the electrolyte.
Iron is coated with a layer of zinc. Zinc is more reactive than iron, so even if the coating is scratched, zinc is oxidised in preference to iron and acts as a sacrificial metal. This protects the iron from oxygen and water.
Answer: x = +6
Answer: 1.10 V
Answer: 0.635 g
Answer: 1930 s (about 32 minutes)