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Aldehydes and ketones: Class 12 Chemistry

Written by Dr. Ayesha Nadeem (Chemistry)

Structure and naming of carbonyl compounds, preparation, physical properties, nucleophilic addition, oxidation and reduction, tests to distinguish aldehydes from ketones, aldol condensation and uses of methanal and propanone.

Key points

Aldehydes (R-CHO) and ketones (R-CO-R') both contain the carbonyl group C=O. In an aldehyde the carbonyl carbon is bonded to at least one hydrogen, so the group is at the end of the chain. In a ketone it is bonded to two carbon atoms. The carbonyl carbon is sp² hybridised, the group is planar with bond angles of about 120°, and the C=O bond is polar, with a partial positive charge on carbon and a partial negative charge on oxygen.

IUPAC names: aldehydes end in al (methanal HCHO, ethanal CH₃CHO) and ketones end in one (propanone CH₃COCH₃, butanone CH₃COC₂H₅). The carbonyl carbon of an aldehyde is number 1. In ketones the chain is numbered to give the C=O the lowest number, as in pentan-2-one. Common names are formaldehyde, acetaldehyde and acetone.

Preparation of aldehydes and ketones:

  • Oxidation of primary alcohols gives aldehydes and of secondary alcohols gives ketones. To stop at the aldehyde the product is distilled off as it forms.
  • Ozonolysis of alkenes gives carbonyl compounds.
  • Hydration of alkynes: ethyne with dilute H₂SO₄ and HgSO₄ gives ethanal, and other alkynes give ketones.
  • Friedel-Crafts acylation of benzene gives aromatic ketones such as phenylethanone.
  • Dry distillation of calcium salts of carboxylic acids gives ketones, for example calcium ethanoate gives propanone.

Aldehydes and ketones are polar, so their boiling points are higher than those of alkanes of similar mass. They are lower than those of alcohols because they cannot form hydrogen bonds with each other. The lower members dissolve in water, since the oxygen forms hydrogen bonds with water. Methanal is a gas, ethanal boils at about 21 °C, and propanone is a liquid that boils at 56 °C.

Nucleophilic addition is the typical reaction. The nucleophile attacks the partly positive carbon, the pi bond breaks and the oxygen gets a negative charge, then takes a proton. Aldehydes are more reactive than ketones, because they have less steric hindrance, and because alkyl groups in ketones push electrons toward carbon and reduce its positive charge.

Examples of nucleophilic addition:

  • HCN gives a cyanohydrin, which adds one carbon: CH₃CHO + HCN → CH₃CH(OH)CN.
  • NaHSO₃ gives a white crystalline addition product with aldehydes and methyl ketones.
  • Grignard reagents give alcohols: methanal gives a primary, other aldehydes a secondary and ketones a tertiary alcohol.
  • 2,4-DNPH (2,4-dinitrophenylhydrazine) gives a yellow or orange precipitate with all aldehydes and ketones, and is a test for the carbonyl group.

Oxidation and reduction:

  • Aldehydes are easily oxidised to carboxylic acids, even by mild oxidising agents. Ketones resist oxidation and need strong agents which break the chain.
  • Reduction with H₂ and Ni, LiAlH₄ or NaBH₄ gives primary alcohols from aldehydes and secondary alcohols from ketones.
  • Clemmensen reduction (Zn/Hg and conc. HCl) turns C=O into CH₂.

Tests that separate aldehydes from ketones:

  • Tollens' test: warm with ammoniacal silver nitrate. An aldehyde gives a silver mirror, and a ketone does not. RCHO + 2[Ag(NH₃)₂]⁺ + 3OH⁻ → RCOO⁻ + 2Ag + 4NH₃ + 2H₂O.
  • Fehling's test: warm with Fehling's solution. An aliphatic aldehyde gives a red-brown precipitate of Cu₂O, and a ketone gives none. Benzaldehyde does not respond.
  • Iodoform test: compounds with CH₃CO- (ethanal and methyl ketones) or CH₃CH(OH)- give a yellow precipitate of CHI₃ with iodine and NaOH.

Aldol condensation: aldehydes and ketones with an alpha hydrogen react in dilute alkali. Two molecules of ethanal join to form 3-hydroxybutanal (an aldol), which loses water on heating to give but-2-enal. Aldehydes with no alpha hydrogen, such as methanal and benzaldehyde, undergo the Cannizzaro reaction in concentrated alkali, where one molecule is oxidised to the acid salt and another is reduced to alcohol.

Uses: methanal as a 40% solution called formalin, used to preserve specimens and to make Bakelite and other resins. Ethanal is used to make ethanoic acid and other chemicals. Propanone is a common solvent (nail polish remover) for paints and plastics. Benzaldehyde is used in perfumes and flavours.

Study tip: Learn the three distinguishing tests with their exact colours, and know which compounds give iodoform. For mechanism questions, always draw the attack of the nucleophile on the carbonyl carbon and the movement of electrons to oxygen. Aldol and Cannizzaro are often asked together, so remember the alpha hydrogen rule that separates them.

Definitions and flashcards

Say the meaning first, then open the card to check.

Carbonyl group

The C=O functional group of aldehydes and ketones.

Nucleophilic addition

Addition of a nucleophile to the carbonyl carbon, breaking the pi bond.

Tollens' reagent

Ammoniacal silver nitrate, which gives a silver mirror with aldehydes.

Fehling's solution

Alkaline copper(II) tartrate, reduced to red Cu₂O by aliphatic aldehydes.

Aldol condensation

Reaction of two carbonyl molecules in dilute alkali to give a hydroxy carbonyl compound.

Cannizzaro reaction

Reaction of an aldehyde with no alpha hydrogen in strong alkali, giving an alcohol and an acid salt.

Alpha hydrogen

A hydrogen on the carbon next to the carbonyl group.

Formalin

A 40% solution of methanal in water, used as a preservative.

Short questions with model answers

These are the kind of questions asked for 2, 3 and 5 marks. Try each one before opening the answer.

Why are aldehydes more reactive than ketones in nucleophilic addition? (2 marks)

In aldehydes the carbonyl carbon has one small H atom and only one electron-donating alkyl group, so it is more positive and less crowded. In ketones two alkyl groups reduce the positive charge and block the approach of the nucleophile.

Why do aldehydes and ketones have lower boiling points than alcohols of similar mass? (2 marks)

Alcohol molecules form hydrogen bonds with each other through O-H. Carbonyl compounds have no hydrogen attached to oxygen, so they only have dipole forces, which are weaker.

How do you distinguish ethanal from propanone using Tollens' test? (2 marks)

Warm each compound with ammoniacal silver nitrate. Ethanal is oxidised to ethanoate and silver ions are reduced to metallic silver, which forms a shining mirror on the tube. Propanone is not oxidised and gives no mirror.

Write the equations for the iodoform test with propanone. (3 marks)

Propanone has a CH₃CO- group. With iodine and sodium hydroxide: CH₃COCH₃ + 3I₂ + 4NaOH → CHI₃ + CH₃COONa + 3NaI + 3H₂O. A yellow precipitate of iodoform with an antiseptic smell shows a positive test.

Explain aldol condensation of ethanal. (3 marks)

In dilute NaOH, a base removes an alpha hydrogen from one ethanal and forms a carbanion. This adds to the carbonyl carbon of a second ethanal, giving 3-hydroxybutanal, CH₃CH(OH)CH₂CHO (aldol). On heating, the aldol loses water and gives but-2-enal, CH₃CH=CHCHO.

Describe the mechanism of addition of HCN to propanone. (5 marks)

In the presence of a trace of base, HCN gives the cyanide ion CN⁻, a strong nucleophile. CN⁻ attacks the partly positive carbon of C=O and the pi electrons move onto oxygen, giving an alkoxide ion. The alkoxide takes H⁺ from HCN and forms the cyanohydrin (CH₃)₂C(OH)CN and regenerates CN⁻. The product has one carbon more than the ketone, and hydrolysis gives a hydroxy acid.

Numericals with worked steps

5.8 g of propanone is reduced completely with hydrogen to propan-2-ol. Find the mass of the alcohol formed. (C = 12, H = 1, O = 16)
  1. CH₃COCH₃ + H₂ → CH₃CH(OH)CH₃.
  2. Molar mass of propanone = 36 + 6 + 16 = 58 g/mol; moles = 5.8 / 58 = 0.1 mol.
  3. Ratio 1 : 1, so 0.1 mol of propan-2-ol forms.
  4. Molar mass of C₃H₈O = 60 g/mol; mass = 0.1 × 60 = 6.0 g.

Answer: 6.0 g of propan-2-ol

23 g of ethanol is oxidised to ethanal with 80% yield. Find the mass of ethanal obtained. (C = 12, H = 1, O = 16)
  1. C₂H₅OH → CH₃CHO (1 : 1 ratio).
  2. Moles of ethanol = 23 / 46 = 0.5 mol.
  3. Theoretical ethanal = 0.5 mol; molar mass 44 g/mol, so 22 g.
  4. Actual mass = 22 × 80 / 100 = 17.6 g.

Answer: 17.6 g of ethanal

4.4 g of ethanal reacts with excess Tollens' reagent. Find the mass of silver deposited. (Ag = 108)
  1. CH₃CHO gives 2 Ag per molecule.
  2. Moles of ethanal = 4.4 / 44 = 0.1 mol.
  3. Moles of Ag = 2 × 0.1 = 0.2 mol.
  4. Mass = 0.2 × 108 = 21.6 g.

Answer: 21.6 g of silver

A saturated aliphatic aldehyde has a molar mass of 58 g/mol. Find its molecular formula and name. (C = 12, H = 1, O = 16)
  1. General formula of a saturated aldehyde: CₙH₂ₙO.
  2. Molar mass = 12n + 2n + 16 = 14n + 16.
  3. 14n + 16 = 58, so 14n = 42 and n = 3.
  4. Formula C₃H₆O with the group -CHO at the end of the chain.

Answer: C₃H₆O, propanal

Common mistakes

  • Saying ketones give a positive Tollens' or Fehling's test. Only aldehydes do (and Fehling's only aliphatic ones).
  • Writing the aldehyde group as -COH. The correct form is -CHO.
  • Thinking 2,4-DNPH separates aldehydes from ketones. It only confirms a carbonyl group.
  • Numbering ketones from the wrong end, so the C=O does not get the lowest number.
  • Forgetting that the iodoform test needs a CH₃CO- group, so propanal and benzaldehyde do not give it.

Practise this chapter

Practice questions and timed test Printable worksheet

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