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Alkanes, alkenes, alkynes and benzene: general formulas, nomenclature, isomerism, preparation, physical properties, characteristic reactions, aromaticity, electrophilic substitution and tests for unsaturation.
Hydrocarbons are compounds of carbon and hydrogen only. Alkanes (CₙH₂ₙ₊₂) are saturated and have only single bonds. Alkenes (CₙH₂ₙ) contain a C=C double bond and alkynes (CₙH₂ₙ₋₂) contain a C≡C triple bond. Both are unsaturated. Aromatic hydrocarbons such as benzene contain a stable ring with delocalised electrons.
In IUPAC naming, find the longest carbon chain that holds the functional group, number it so the double or triple bond gets the lowest number, then name and number the side groups in alphabetical order. Examples: CH₃CH₂CH=CH₂ is but-1-ene and CH₃C≡CCH₃ is but-2-yne. Branched alkanes are named as alkyl derivatives, as in 2-methylpropane.
Types of isomerism:
In alkanes carbon is sp³ hybridised with bond angles of 109.5°. In alkenes carbon is sp² with a planar shape and angle 120°, and the double bond is one sigma and one pi bond. In alkynes carbon is sp with a linear shape, 180°, and the triple bond is one sigma and two pi bonds. The C=C bond length is about 134 pm, which is shorter than C-C (154 pm).
Preparation of alkanes, alkenes and alkynes:
Alkanes are fairly unreactive because C-C and C-H bonds are strong and non-polar. Their main reactions are combustion, CH₄ + 2O₂ → CO₂ + 2H₂O, and free radical substitution with halogens in sunlight. Substitution goes through initiation (Cl₂ splits into two Cl· radicals), propagation (Cl· + CH₄ → HCl + CH₃·, then CH₃· + Cl₂ → CH₃Cl + Cl·) and termination (two radicals combine).
Alkenes and alkynes are reactive because the pi bond is weaker and electron rich. They undergo electrophilic addition. Examples: addition of H₂ (Ni, giving an alkane), Br₂ (giving a dibromoalkane), HBr and water (with acid catalyst). Ethyne adds two moles of reagent, first forming an alkene derivative and then a saturated product.
Markovnikov's rule: when HX adds to an unsymmetrical alkene, the hydrogen goes to the carbon that already has more hydrogen atoms. Reason: the more substituted carbocation is more stable. So propene plus HBr gives 2-bromopropane as the major product.
Tests for unsaturation:
Benzene C₆H₆ is a planar ring of six sp² carbons, all C-C bonds equal (139 pm), with delocalised pi electrons above and below the ring. It is stable and follows Hückel's rule (4n + 2 pi electrons, here 6). It prefers substitution to addition. Kekulé's structure shows alternating double bonds, but the real molecule is a resonance hybrid.
Electrophilic substitution of benzene keeps the ring intact. Nitration uses conc. HNO₃ and conc. H₂SO₄ at about 50 °C to give nitrobenzene. Halogenation uses Cl₂ or Br₂ with FeCl₃ or FeBr₃. Friedel-Crafts alkylation with CH₃Cl and anhydrous AlCl₃ gives toluene. Addition happens only under severe conditions, such as hydrogenation to cyclohexane.
A group already on the ring directs the next substituent. The CH₃, OH and halogen groups direct to ortho and para positions. The NO₂, CHO and COOH groups direct to the meta position. Most groups that direct ortho and para activate the ring, while the others deactivate it (halogens deactivate slightly but still direct ortho and para).
Study tip: Learn each reaction with its reagent, condition and product, as a short chain: reagent, then condition, then product. Practise naming five or six alkenes and alkynes every day. For mechanism questions write each step on its own line and show the movement of the species clearly.
Say the meaning first, then open the card to check.
A hydrocarbon with only single bonds between carbon atoms.
A hydrocarbon with at least one double or triple carbon-carbon bond.
Compounds with the same molecular formula but different structures.
A species that is short of electrons and attacks electron-rich sites.
An atom or group with an unpaired electron.
In addition of HX to an unsymmetrical alkene, H goes to the carbon with more hydrogens.
A cyclic, planar compound with delocalised pi electrons and 4n + 2 of them.
Representing a molecule by two or more structures differing only in the position of electrons.
| Name | Formula | What it means |
|---|---|---|
| Alkanes | CₙH₂ₙ₊₂ | General formula of saturated chain hydrocarbons |
| Alkenes | CₙH₂ₙ | General formula with one C=C bond |
| Alkynes | CₙH₂ₙ₋₂ | General formula with one C≡C bond |
| Hückel's rule | Number of pi electrons = 4n + 2 | Condition for aromaticity (n = 0, 1, 2 ...) |
These are the kind of questions asked for 2, 3 and 5 marks. Try each one before opening the answer.
Alkenes have a pi bond that is weaker and rich in electrons, so electrophiles attack it and add across the double bond. Alkanes have only strong sigma bonds, so they react only with a free radical that replaces a hydrogen atom.
When a molecule HX adds to an unsymmetrical alkene, the hydrogen attaches to the doubly bonded carbon with more hydrogen atoms. Example: CH₃CH=CH₂ + HBr gives CH₃CHBrCH₃ (2-bromopropane) as the main product.
Shake each gas with bromine water or with dilute alkaline KMnO₄. Ethene decolourises the orange bromine water (or the purple permanganate) because it adds across the double bond. Ethane does not change the colour.
Initiation: in sunlight Cl₂ splits into two chlorine radicals, Cl₂ → 2Cl·. Propagation: Cl· + CH₄ → HCl + CH₃·, then CH₃· + Cl₂ → CH₃Cl + Cl·. This repeats as a chain. Termination: radicals combine to end the chain, for example Cl· + Cl· → Cl₂ or CH₃· + Cl· → CH₃Cl.
Benzene is a planar hexagon of six sp² carbons. Each carbon forms sigma bonds with two carbons and one hydrogen, and the left over p orbitals overlap sideways to give a cloud of six delocalised pi electrons above and below the ring. All C-C bonds are equal at 139 pm, between a single and a double bond. This is shown by resonance between two Kekulé structures, and it explains the high stability and the preference for substitution.
Benzene is warmed at about 50 °C with a mixture of concentrated nitric acid and concentrated sulfuric acid. The nitronium ion NO₂⁺ is the electrophile. C₆H₆ + HNO₃ → C₆H₅NO₂ + H₂O. The product is nitrobenzene, a pale yellow oily liquid.
Answer: 28 dm³ of O₂ and 33 g of CO₂
Answer: C₃H₆
Answer: 16 g of bromine
Answer: 92.3% carbon