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Macromolecules: Class 12 Chemistry

Written by Dr. Ayesha Nadeem (Chemistry)

Polymers and polymerisation, addition and condensation polymers, natural and synthetic polymers, carbohydrates, proteins and amino acids, lipids, nucleic acids, and the uses and environmental effects of plastics.

Key points

Macromolecules are very large molecules with molar masses from several thousand up to millions. Most are polymers, built by joining many small units called monomers. The process is polymerisation. The number of monomer units in the chain is the degree of polymerisation (n). Polymers can be natural (starch, proteins, cellulose, rubber, DNA) or synthetic (polythene, PVC, nylon).

Types of polymerisation:

  • Addition polymerisation: monomers with a C=C bond join one after another without losing any atoms. The polymer has the same empirical formula as the monomer. Examples: ethene to polythene, chloroethene to PVC, tetrafluoroethene to PTFE (Teflon) and propene to polypropene.
  • Condensation polymerisation: monomers with two reactive groups join with loss of a small molecule, usually water. Examples: nylon-6,6 from hexane-1,6-diamine and hexanedioic acid, and polyester (terylene) from ethane-1,2-diol and benzene-1,4-dicarboxylic acid.

Addition polymers form by a free radical chain mechanism. An initiator such as a peroxide makes radicals (initiation). The radical attacks a monomer and the new radical attacks the next (propagation), and the chain stops when two radicals meet (termination). Low density polythene is made at high pressure and temperature by this route, while high density polythene is made with Ziegler-Natta catalyst at low pressure and has a more regular, tightly packed structure.

Polymers can be linear, branched or cross-linked. Linear and branched polymers soften on heating and are called thermoplastics (polythene, PVC). Cross-linked polymers cannot be remoulded after setting and are called thermosetting plastics (Bakelite, melamine). Natural rubber is a polymer of isoprene (2-methylbuta-1,3-diene) that becomes harder and more elastic when heated with sulfur, called vulcanisation.

Carbohydrates are polyhydroxy aldehydes or ketones and their polymers, with a general formula near Cₓ(H₂O)ᵧ:

  • Monosaccharides cannot be hydrolysed further: glucose (an aldose), fructose (a ketose) and galactose, all C₆H₁₂O₆.
  • Disaccharides give two monosaccharides: sucrose (glucose and fructose), maltose (two glucose) and lactose (glucose and galactose). The units join through a glycosidic bond.
  • Polysaccharides give many monosaccharides: starch (storage in plants, a mixture of amylose and amylopectin), glycogen (storage in animals) and cellulose (structural, in plant cell walls, made of β-glucose).

Glucose reduces Tollens' and Fehling's reagents, so it is a reducing sugar. Sucrose is not reducing because the glycosidic bond uses the carbon atoms that would give the aldehyde and ketone groups. Starch turns blue-black with iodine solution. Hydrolysis with dilute acid or enzymes breaks the glycosidic bonds, as in (C₆H₁₀O₅)ₙ + nH₂O → nC₆H₁₂O₆.

Proteins are polymers of alpha amino acids, H₂N-CHR-COOH. Amino acids are amphoteric, since they have both a basic NH₂ group and an acidic COOH group, and in water they exist as zwitterions. Two amino acids join by a peptide bond (-CO-NH-) with loss of water. Chains of many amino acids form polypeptides. Twenty common amino acids occur in proteins, and eight to nine of them are essential in the human diet.

Levels of protein structure:

  • Primary: the sequence of amino acids in the chain.
  • Secondary: regular folding held by hydrogen bonds, as the alpha helix and beta pleated sheet.
  • Tertiary: the overall three-dimensional shape from interactions between side chains (hydrogen bonds, disulfide bridges, ionic and hydrophobic interactions).
  • Quaternary: the arrangement of two or more polypeptide chains, as in haemoglobin.

Denaturation is the loss of the natural shape of a protein caused by heat, strong acid or alkali, or heavy metal salts. Biological activity is lost. Enzymes are protein catalysts that are very specific and work best at certain temperature and pH values. Proteins give a purple colour in the biuret test and a yellow colour with concentrated nitric acid (xanthoproteic test).

Lipids are fats, oils and waxes. Fats and oils are triesters of glycerol with three fatty acids (triglycerides). Fats are solids with mostly saturated acids, and oils are liquids with unsaturated acids. Alkaline hydrolysis gives glycerol and soap. Lipids store energy (about 38 kJ/g, more than carbohydrates), insulate the body and form cell membranes.

Nucleic acids (DNA and RNA) are polymers of nucleotides. A nucleotide has a sugar (deoxyribose in DNA, ribose in RNA), a phosphate group and a nitrogenous base. DNA has A, T, G and C, and RNA has U in place of T. DNA is a double helix with bases paired A with T and G with C by hydrogen bonds. It stores genetic information, and RNA helps to make proteins.

Synthetic polymers are useful but many do not break down in nature. Plastic waste blocks drains and harms animals. Burning PVC releases toxic gases. Remedies are reducing use, reusing, recycling and using biodegradable polymers.

Study tip: Prepare a table of the main polymers with monomer, type of polymerisation and one use. For biomolecules, learn one clear diagram in words for each: peptide bond, glycosidic bond, and base pairing. Numericals are simple ratio problems, so write the balanced equation or the unit mass first.

Definitions and flashcards

Say the meaning first, then open the card to check.

Monomer

A small molecule that joins with others to form a polymer.

Polymer

A large molecule made by joining many monomer units.

Degree of polymerisation

The number of monomer units in a polymer chain.

Thermoplastic

A polymer that softens on heating and can be remoulded.

Glycosidic bond

The C-O-C link joining two sugar units.

Peptide bond

The amide bond -CO-NH- joining two amino acids.

Denaturation

Loss of the natural three-dimensional shape of a protein.

Zwitterion

An ion with both a positive and a negative charge, formed by an amino acid.

Formula sheet

NameFormulaWhat it means
Degree of polymerisationn = molar mass of polymer / molar mass of monomerNumber of repeating units in the chain
Hydrolysis of starch(C₆H₁₀O₅)ₙ + nH₂O → nC₆H₁₂O₆Starch breaking down to glucose
Peptide of x residuesMass = sum of amino acids − (x − 1) × 18x amino acids joined by x − 1 peptide bonds

Short questions with model answers

These are the kind of questions asked for 2, 3 and 5 marks. Try each one before opening the answer.

Differentiate between addition and condensation polymerisation. (2 marks)

In addition polymerisation unsaturated monomers add to each other and no atoms are lost, as in ethene to polythene. In condensation polymerisation monomers with two functional groups join and eliminate a small molecule such as water, as in nylon-6,6.

Why is sucrose a non-reducing sugar although glucose is reducing? (2 marks)

In sucrose, the glycosidic bond joins the carbon of glucose that carries the aldehyde group with the carbon of fructose that carries the ketone group. No free aldehyde or ketone group remains to reduce Tollens' or Fehling's reagent.

What is a peptide bond? Show how it forms between two glycine molecules. (3 marks)

A peptide bond is the amide linkage -CO-NH- formed between the carboxyl group of one amino acid and the amino group of another, with loss of water. H₂N-CH₂-COOH + H₂N-CH₂-COOH → H₂N-CH₂-CO-NH-CH₂-COOH + H₂O. The product is the dipeptide glycylglycine.

Distinguish between starch and cellulose. (3 marks)

Both are polymers of glucose. Starch is an energy store in plants and is made of α-glucose units (amylose is linear and amylopectin is branched). Cellulose is the structural material of plant cell walls and is made of β-glucose units in straight chains. Humans can digest starch but not cellulose. Starch gives a blue-black colour with iodine, and cellulose does not.

Describe the four levels of protein structure. (5 marks)

Primary structure is the sequence of amino acids joined by peptide bonds. Secondary structure is the regular folding into alpha helix or beta sheet held by hydrogen bonds between peptide groups. Tertiary structure is the overall three-dimensional shape formed by interactions between R groups: hydrogen bonds, disulfide bridges, ionic attractions and hydrophobic effects. Quaternary structure is the way separate polypeptide chains join in one protein, as the four chains in haemoglobin. The shape decides the function.

Explain how the double helix structure of DNA is held together. (5 marks)

DNA has two strands of nucleotides wound around each other. The sugar and phosphate groups form the backbone outside, and the bases point inward. Adenine pairs with thymine through two hydrogen bonds, and guanine pairs with cytosine through three. The base pairing makes the two strands complementary, so each can act as a template for copying.

Numericals with worked steps

A sample of PVC has a molar mass of 62 500 g/mol. Find its degree of polymerisation. (Monomer CH₂=CHCl: C = 12, H = 1, Cl = 35.5)
  1. Molar mass of C₂H₃Cl = 24 + 3 + 35.5 = 62.5 g/mol.
  2. n = 62 500 / 62.5.
  3. n = 1000.

Answer: n = 1000

Find the molar mass of the tripeptide formed from three glycine molecules. (Glycine C₂H₅NO₂ = 75 g/mol, water = 18)
  1. Three amino acids make 2 peptide bonds.
  2. Two molecules of water are lost.
  3. Mass = 3 × 75 − 2 × 18 = 225 − 36 = 189 g/mol.

Answer: 189 g/mol

Find the mass of glucose obtained by complete hydrolysis of 81 g of starch. (C = 12, H = 1, O = 16)
  1. (C₆H₁₀O₅)ₙ + nH₂O → nC₆H₁₂O₆.
  2. Mass of repeating unit C₆H₁₀O₅ = 72 + 10 + 80 = 162 g/mol.
  3. Moles of units = 81 / 162 = 0.5 mol.
  4. Each unit gives one glucose (180 g/mol), so mass = 0.5 × 180 = 90 g.

Answer: 90 g of glucose

171 g of sucrose is hydrolysed completely. Find the mass of glucose and of fructose formed. (Sucrose C₁₂H₂₂O₁₁ = 342 g/mol; glucose and fructose = 180 g/mol)
  1. C₁₂H₂₂O₁₁ + H₂O → C₆H₁₂O₆ (glucose) + C₆H₁₂O₆ (fructose).
  2. Moles of sucrose = 171 / 342 = 0.5 mol.
  3. Each product is 0.5 mol, so mass = 0.5 × 180 = 90 g.

Answer: 90 g of glucose and 90 g of fructose

Common mistakes

  • Saying addition polymers lose small molecules. That is condensation polymerisation.
  • Forgetting to subtract the water when finding the mass of a peptide, or subtracting one water too many (it is x − 1 for x residues).
  • Writing starch as a polymer of fructose or cellulose as a polymer of α-glucose. Cellulose has β-glucose.
  • Mixing up thermoplastic and thermosetting plastics.
  • Writing U in DNA or T in RNA. DNA has thymine, and RNA has uracil.

Practise this chapter

Practice questions and timed test Printable worksheet

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