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Basic concepts
Written by Dr. Ayesha Nadeem (Chemistry)
8 Class 11 Chemistry questions with answers and explanations.
Printable worksheet with answer key
All questions with answers
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How many moles are in 44 g of CO2? (C = 12, O = 16)
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Correct answer: 1
Molar mass = 44 g/mol, so 44 g is 1 mole.
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The number of molecules in 2 moles of a gas is:
- 1 6.02 x 10^23
- 2 1.204 x 10^24
- 3 3.01 x 10^23
- 4 12 x 10^23 atoms
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Correct answer: 1.204 x 10^24
2 x 6.02 x 10^23 = 1.204 x 10^24.
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The empirical formula of a compound with the molecular formula C6H12O6 is:
- 1 CHO
- 2 CH2O
- 3 C2H4O2
- 4 C3H6O3
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Correct answer: CH2O
Divide the subscripts by 6 to get CH2O.
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The limiting reagent in a reaction is the one that:
- 1 Is used up first
- 2 Is in excess
- 3 Is a catalyst
- 4 Is a gas
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Correct answer: Is used up first
It runs out first and limits the amount of product.
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What volume does 1 mole of any gas occupy at STP?
- 1 1 dm3
- 2 24 dm3
- 3 22.4 dm3
- 4 11.2 dm3
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Correct answer: 22.4 dm3
At STP one mole of an ideal gas occupies 22.4 dm3.
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The mass of one mole of NaCl is: (Na = 23, Cl = 35.5)
- 1 35.5 g
- 2 23 g
- 3 58.5 g
- 4 81.5 g
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Correct answer: 58.5 g
23 + 35.5 = 58.5 g.
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Percentage yield is:
- 1 Theoretical yield / actual yield x 100
- 2 Actual yield / theoretical yield x 100
- 3 Actual yield x 100
- 4 Theoretical yield only
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Correct answer: Actual yield / theoretical yield x 100
It compares what you get with the maximum possible.
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Avogadro's number is the number of particles in:
- 1 One litre
- 2 One gram
- 3 One mole
- 4 One kilogram
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Correct answer: One mole
One mole has 6.02 x 10^23 particles.
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