NED · Mathematics · 24 questions
Name: ____________________ Date: ____________
cosec 2x − cot 2x is equal to:
The limit of (x² − 4) ÷ (x² − 2x) as x tends to 2 is:
The equation of the normal to the curve y = 5 − x² at the point where x = 2 is:
The value of the integral of 3x² from 0 to 2 is:
The dot product of the vectors (2, 3, 1) and (1, −1, 2) is:
The cross product i × k is equal to:
The sum of the first 10 terms of the arithmetic progression 5, 8, 11, … is:
The coefficient of x⁴ in the expansion of (1 + x)⁸ is:
The determinant of the matrix with rows (1, 2, 3), (0, 1, 4) and (5, 6, 0) is:
The value of i¹⁰, where i = √−1, is:
The equation of the tangent to the parabola y = x² at the point (1, 1) is:
The eccentricity of the hyperbola x²/9 − y²/16 = 1 is:
The derivative of x eˣ with respect to x is:
The integral of x eˣ with respect to x is:
The number of different arrangements of 5 people in a row is:
Two fair dice are thrown. The probability that the sum is 8 is:
The distance of the point (1, 2) from the line 3x + 4y − 10 = 0 is:
The inverse of the function f(x) = eˣ is:
The solution of |2x − 3| < 5 is:
If cos x = 3/5, then cos 2x is:
The sum to infinity of the geometric series 9 + 3 + 1 + … is:
The limit of (sin 3x) ÷ x as x tends to 0 is:
The area between the curve y = x², the x-axis and the line x = 3 is:
The magnitude of the vector 2i − 2j + k is:
1. C, 2. B, 3. A, 4. A, 5. C, 6. A, 7. B, 8. B, 9. C, 10. B, 11. C, 12. A, 13. C, 14. D, 15. C, 16. C, 17. A, 18. A, 19. A, 20. C, 21. A, 22. B, 23. D, 24. A
cosec 2x − cot 2x = (1 − cos 2x) ÷ sin 2x = 2 sin²x ÷ (2 sin x cos x) = tan x.
The expression simplifies to (x + 2) ÷ x, which is 2 at x = 2.
At x = 2 the point is (2, 1) and the tangent slope is −4, so the normal slope is 1/4 and the line is 4y − x = 2.
The antiderivative is x³, which gives 8 − 0.
The product is 2 − 3 + 2 = 1.
Using the right hand rule, k × i = j, so i × k = −j.
The sum is (10 ÷ 2)(2 × 5 + 9 × 3) = 5 × 37 = 185.
The coefficient is 8C4 = 70.
Expanding along the first row gives −24 + 40 − 15 = 1.
i⁴ = 1, so i¹⁰ = i² = −1.
The slope is 2x = 2 at x = 1, so y − 1 = 2(x − 1).
Here c² = 9 + 16 = 25, so e = c ÷ a = 5/3.
The product rule gives eˣ + x eˣ.
Integration by parts gives x eˣ − eˣ.
The number is 5! = 120.
Five outcomes give a sum of 8: (2, 6), (3, 5), (4, 4), (5, 3) and (6, 2).
The distance is |3 + 8 − 10| ÷ 5 = 1/5.
The natural logarithm undoes the exponential.
The inequality means −5 < 2x − 3 < 5.
cos 2x = 2 cos²x − 1 = 18/25 − 1 = −7/25.
The sum is 9 ÷ (1 − 1/3) = 13.5.
The limit is 3 × (sin 3x ÷ 3x), which tends to 3.
The area is the integral of x² from 0 to 3, which is 27 ÷ 3 = 9.
The magnitude is √(4 + 4 + 1) = 3.